Problem with factoring?

Question

x^3(is less than or equal to) x^2-x+1

Answer 1

x^3 <= x^2 - x + 1

x^3 - x^2 + x - 1 <= 0

x^2 (x-1) + (x-1) <= 0

(x^2 + 1)(x-1) <= 0

Since x^2 +1 is always positive, we can divide both sides by it, giving:

x-1 <= 0

x <= 1

Answer 2

x³-x²+x-1<=0

x²(x-1) + (x-1) <= 0

(x²+1)(x-1) <= 0

x<=1

Answer 3

Please make your question clear,what do you want to know?

Answer 4

x^3 <= x^2 - x + 1

x^3 - x^2 + x - 1 <= 0

x^2(x - 1) + 1(x - 1) <=0

(x^2 + 1)(x - 1) <= 0

(x + 1)(x - 1)(x - 1) <= 0

x <= -1 ...OR... x <= 1

since x is always positive... therefore x <= 1