Problem with vectors . . . . ?

Question

Hi.

I have the vector 3i - 2j + 4k that describes the movement of a particle. I need to change this so that the particle moves along the same line but with speed 2.

How do I do this? Please show your answer step by step and explanations of each step are appreciated.

Thank you!

Answer 1

I got your message.

For this problem, you can normalize it first, and then times two.

sqrt[3^2+(-2)^2+4^2] = sqrt(29)

So, the new vector is [2sqrt(29)/29](3i - 2j + 4k)

Answer 2

first of all get a life loser and simply ask your teacher instead of asking it on the net.

it's answer is divide it by square root of 3 square +2 square

+4 square and then multiply by 2