Question:

Prove that cos^4A - sin^4A= cos 2A?

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Prove that cos^4A - sin^4A= cos 2A?

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  1. cos^4A -sin^4A =(cos^2 -sin^2A)(cos^2 A +sin^2A) =

    cos^2A -sin^2A =cos2A (a double angle identity)


  2. cos^4 A - sin^4 A = (1 + cos 2A / 2)^2 - (1 - cos 2A / 2)^2       [double angle formulae]

    = (1 + 2 cos 2A + cos^2 2A - 1 + 2 cos 2A - cos^2 2A) / 4

    = 4 cos 2A / 4

    = cos 2A

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