Question:

Proving trigonometry function?

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prove that tan(x)+cot(x)=sec(x)*csc(x)

please show working out

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4 ANSWERS


  1. tan x + cot x

    = sin x / cos x + cos x / sin x

    = (sin² x + cos² x) / sin x cos x

    = 1 / cos x sins x

    = sec x csc x .


  2. sinx/cosx + cosx/sinx

    =(sin^2 x + cos62 x)/(cosx sinx)

    =1/(cosx sinx)

    =1/cosx * 1/sinx

    =secx cscx

  3. tanx=sinx/cosx    cotx=cosx/sinx   secx=1/cosx    cscx=1/sinx

    tan(x)+cot(x)= 1/cosx*1/sinx

    tan(x)+cot(x)= 1/cos(x)sin(x)

    tan(x)+cot(x)=tan(x)+cot(x)

  4. sinx/cosx + cosx/sinx =

    (sin²x + cos²x) / sinx*cosx =

    1 / sinx*cosx = secx*cscx

    Good luck.

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