Pythagorean Theorem Question! Help someone!?

Question

In slow-pitch softball, the distance between consecutive bases is 65 feet. The pitcher's plate is located on a line between second base and home plate, 50 feet from home plate. How far is the pitcher's plate from second base? Justify your answer. Please explain how you got it, cause I don't get it at all!

Answer 1

The Pythagorean theorem is a^2 + b^2=c^2

You know that from home to 1st base is 65 feet and from 1st to 2nd base is 65 feet.

So, lets call home to 1st ‘a’ and 1st to 2nd ‘b’

a^2 + b^2 = 65^2 + 65^2= 8450

Then take the square root of 8450= 91.924 feet

You know that from home to the pitchers mound is 50 feet

91.924 feet – 50 feet = 41.924 feet from the pitchers mound to 2nd base

If you are to round it up it would be 42 feet

Answer 2

ok draw the sqare to represent the 4 baces. draw a line connecting home to 2nd. use Pythagorean theorem to find the line you just drew.

65^2+65^2=c^2

8450=c^2

~92=c

~=about

ok then you subtract 50 from that and you get the answer

~42

Answer 3

The theorem is a^2+b^2=c^2. Draw it out then work it.