Question:

Pythagorean Theorem?

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What is the hypotenuse of a triangle if one side is 11 yrd and the other is 60 yrd

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  1. Remember the formula a^2+b^2=c^2 where c is always the hypotenuse.

    So, using the pythagorean formula we have

    11^2+60^2=c^2

    121+3600=c^2

    3721=c^2

    Now square root both sides to get

    61=c

    The hypotenuse is 61 yards.

    Have a good day!


  2. 61 yards. ;;;

    11^2 + 60^2 = 3721

    a squared + b squared = csquared.

    c= hypot.

    then you square root what you got ^___.

  3. sqrt(3721)=61 yards

  4. 61yd

  5. Pythagoran theorm:

    h^2 = x^2 + y^2

    h^2 = 11^2 + 60^2

    |h| = 61 yd

  6. a^2+b^2=c^2

    soo its 61

  7. square root  of   3600 + 121

  8. There is a good free lesson that clearly explains how to do Pythagoras' Theorem at

    http://www.mathspower.com.au/Pages/Sampl...

    When you get there, scroll down to "Year 6-7" and it is the second sample lesson under the "Year 6-7" heading.


  9. The pythagorean theorem says that the square of the hypotenuse is equal to the total of the squares of the other sides.

    So, begin by taking the square of 11, and 60. ie, 11 * 11 plus 60 * 60.

    Then, take the square root of that total to figure out the hypotenuse length.

    It's much better to actually read your text book and understand the math topic, than to just hope someone tells you the answer here. You're very lazy!
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