QUADRATIC FUNCTION...MATH HELP/QUESTION.....10 PTS.!!!! read. :))?

Question

Says:

Determine the inverse functions for the functions below. Begin by switching variables in the original function, then solving for the 'new' y.

state the Invariant.

1. y=x^2 (quadratic function)

10 pts.

:)

Answer 1

can't quite figure out the question here coz whereas

y=x^2

x=sq root of y

Answer 2

solving for x first:

x=+-(y)^0.5

-->y= (x)^0.5

but since u may have only pos. numbers in a root,  the neg. x-values r undefined and u'll have only half of a parable flipped 90° opening vs pos x.

Answer 3

f(x) = x^2

f(x)^-1 = x = y^2

y = sqrt(x) therefore,

f(x)^-1 = sqrt(x) or,

f(x)^-1 = x^(1/2)

Answer 4

The given equation is

                   y=x^2

Now, replace x with y and vice-versa as follows

                  x=y^2

now, find the value of y in term of x as follows

                  y=x^1/2

               this is your solution

Answer 5

x=y^2

take sqrt of both sides

+ or -sqrt(x) = y

Answer 6

we are given y=x^2

taking sq rt x=+/-sq root(y)

now to find the inverse interchange the fnctns.

thus inverse is y=+/-sq root of (x)