Quadratic formula math problem..?

Question

solve using quadratic formula and show all work please:

1) 4x(squared) = 6x + 2

Answer 1

4x^2 - 6x - 2 = 0

x = [-b +/- sqrt(b^2-4ac)]/(2a)

a = 4

b = -6

c - -2

x = [6 +/- sqrt((-6)^2-4(4)(-2))]/(2(4))

x = [6 +/- sqrt(36+32)]/8

x = [6 +/- sqrt(68)]/8

x = [6 +/- sqrt(4*17)]/8

x = [6 +/- 2sqrt(17)]/8

x = 3/4 + sqrt(17)/4 and x = 3/4 - sqrt(17)/4

Answer 2

subtract 4x^2 on both sides: -4x^2+6x+2=0

plug in the numbers in the formula a= -4 b= 6 c= 2

x= -6 + or - the square root of 6^2 - 4(-4)(2)

   ----------------------------------------...

                      2(-4)

= -6 + or - the square root of  36+32

   ----------------------------------------...

                   -8

= -6 +/-  the square root of 68

   ---------------------------------------

                  -8

= -6 +/- the sq root of 4 x 17

   ---------------------------------------

                   -8

= - 6 +/- 2 square root of 17

   ----------------------------------------

                   -8

= -3 +/- the square root of 17

  ----------------------------------------...

                   -4

i got this because 2 goes into -6, 2, and -8

this is your answer but if you want it simplified one more time:

-3 + square root of 17              -3 - sq root of 17

--------------------------------   ,     ----------------------------------

           -4                                         -4

hope this helps

Answer 3

quad. formula - x = -b +/- √(b^2 - 4ac) / 2a

step 1: Subtract 4x^2 on both sides (4x^2 - 4x^2 = -4x^2 + 6x + 2,  

-4x^2 + 6x + 2 = 0)

Step 2: -4x^2 = a; 6x = b; 2 = c

Step 3: Plug it in - -6x +/- √ [ -6^2 - 4(-4)(2) ] / 2(-4)

Step 4: Simplify parentheses -6^2 - 4(-4)(2) = 36 + 32 = 68

Step 5: Find square root of 68 (4 x 17 = 68 and has a perfect square, 4, so you get √4√17, or just 2√17.)

Step 6: Simplify bottom: 2(4) = 8

Step 7: Now you have -6x +/- 2√17 / 8

Step 8: Simplify fraction by dividing both sides by 2

-6/ 2 = -3;  -2√17/ 2 = -1√17; 8/2 = 4

Your final answer is x= -3 +/-  -1√17 / 4

Answer 4

4x^2 = 6x +2

4x^2 -6x -2 = 0

x = [6 +/- sqrt(6^2 -4(4)(-2)]/(2*4)

x = [6 +/- sqrt(36+32)]/8

x = [6 +/- 2sqrt(17)]/8

x = .75 +/- .25sqrt(7)

x = .75 + .25sqrt(17), and

x = .75 - .25sqrt(17)

Answer 5

4(x^2) - 6x - 2 = 0

2(x^2) - 3x -1 = 0

quadratic formula, a=2, b=-3, c=-1

x = (3 +- sqrt(17)/4

Answer 6

4x² = 6x + 2

4x² - 6x - 2 = 0

a = 4, b = -6, c = -2

x1 = [-b+ (b² - 4ac)^½]/(2a)

x1 = [6 + (36 - -32)^½]/(8)

x1 = (6 + 68^½) / 8

x2  = [-b - (b² - 4ac)^½]/(2a)

x2 = (6 - 68^½) / 8