Quadratic formula?math?

Question

2x+6x+8 shud u common factor 2 than put in quadd formula so

it would be 1+-sqrt etc.. or it doesnt matter just leave it and do 2+- swrt etc.

Answer 1

You can't use quadratic formula in this case, for two reasons:

1. 2x+6x+8 is just an expression, not an equation.

2. x is raised only to the 1st power. Quadratic means that the variable has an exponent of 2, as in x^2.

Answer 2

that is not a quadratic equation...

Answer 3

when u take common of 2

then according to formula

x=-3+-sqrt(9-32)/2a

Answer 4

It does not matter. You go ahead use the quadratic formula using the given coefficients because  the divisor 2a will just cancel out the common factor.

Answer 5

Your question is really not clear, please make it clear what do you want to ask?

Answer 6

assuming the question is solving

2x^2 + 6x +4 = 0

x^2 + 3x + 2 = 0

(x+1)(x+2) = 0

or using the quadratic formula

you have a = 2, b = 6, c = 4

x = [-b +/- sqrt(b^2 - 4ac)] all over 2a

its easier to get rid of common factors, but you will get the right answer either way    

Answer 7

check the equation, its not a quadratic equation. :D

Answer 8

Question Number 1 :

For this equation 2*x^2 + 6*x + 8 = 0 , answer the following questions :

A. Find the roots using Quadratic Formula !

Answer Number 1 :

The equation 2*x^2 + 6*x + 8 = 0 is already in a*x^2+b*x+c=0 form.

As the value is already arranged in a*x^2+b*x+c=0 form, we get the value of a = 2, b = 6, c = 8.

1A. Find the roots using Quadratic Formula !

  Use the formula,

    x1 = (-b+sqrt(b^2-4*a*c))/(2*a) and x2 = (-b-sqrt(b^2-4*a*c))/(2*a)

  We had know that a = 2, b = 6 and c = 8,

  then the value a,b and c in the abc formula, can be subtituted.

  So x1 = (-(6) + sqrt( (6)^2 - 4 * (2)*(8)))/(2*2) and x2 = (-(6) - sqrt( (6)^2 - 4 * (2)*(8)))/(2*2)

  Which can be turned into x1 = ( -6 + sqrt( 36-64))/(4) and x2 = ( -6 - sqrt( 36-64))/(4)

  Which can be turned into x1 = ( -6 + sqrt( -28))/(4) and x2 = ( -6 - sqrt( -28))/(4)

  Which can be turned into x1 = ( -6 + sqrt(28)*sqrt(-1))/(4) and x2 = ( -6 - sqrt(28)*sqrt(-1))/(4)

  Since sqrt(-1) = i,

  So we get x1 = ( -6 + 5.29150262212918*i )/(4) and x2 = ( -6 - 5.29150262212918*i )/(4)

  So we got the answers as x1 = -1.5 + 1.3228756555323*i and x2 = -1.5 - 1.3228756555323*i