Question Below..?

Question

A Boeing 727-200 jet taking off from Lansing airport accelerates from rest for 31.0 s before leaving the ground. Its acceleration is 2.23 m/s2.

Assuming that the acceleration is constant, calculate the plane's speed at take off.

What is the take off speed in mi/hr?

Answer 1

31.0s x 2.23 m/s/s=69.13m/s

convert from m/s to mph

69.13m/s x 3600s/hour x 1609.34meters/mile=154.63mph

What class is this for?  You really should do your own homework.   Your profile shows you asked the max Q's for the day.

Answer 2

Vr calcuated for GTOW for given pressure altitude. Airspeed is indicated, so actual ground speed is irrevaelant, also a b-727 does not measure speed by MPH, it is measured in KTAS, or Mach numbers when in cruise. Do your own physics homework.

Answer 3

Here, at = v, so [(2.23m/s)/s]31.0s ≈ 69.1m/s.

[(69.13m)(39.37in/m)(ft/12in)

(mi/5280ft)]/[(sec)(min/60sec)

(hr/60min)] ≈ 155mi/hr.

Answer 4

A loaded 727-200 at average weight in normal conditions requires several things......V1, V2, then rotation, which comes at about 155 KTAS

Answer 5

You don't cover Gross Weight, temperature, etc.

So, I am going to say 154 Miles per hour.  That will change, however, based on the other variables not listed.

Check out this page for some interesting info on the 727-200:

http://www.airliners.net/info/stats.main...