Question:

Question With Reagent Equation?

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Identify the limiting reagent and the volume of CO2 formed when 11 L CS2 reacts with 18 L O2 to produce CO2 gas and SO2 gas at STP.

A.) CS2; 5.5 L CO2

B.) O2; 6.0 L CO2

C.) CS2; 11 L CO2

D.) O2; 27 L CO2

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  1. The reaction is:

    CS2 + 3O2 -----> CO2 + 2SO2

    1 L of CS2 reacts with 3 L O2.

    11 L CS2 x (3 L O2 / 1 L CS2) = 33 L O2

    There are only 18 L of O2 present, not the 33 L needed to react with all the CS2. Therefore, O2 is the limiting reagent.

    3 L O2 produces 1 L CO2

    18 L O2 x (1 L CO2 / 3 L O2) = 6 L CO2.

    The answer is:

    B) O2; 6 L CO2

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