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a regular 64 agon has how many diagonals

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  1. diagonals = n(n-3)/2 =1952


  2. Okay, you have a 64 sided regular polygon.  The formula for the number of distinct diagonals (see link below for how to derive the formula) is:

    d = n(n-3)/2

    d = 64(64-3)/2

    d = 64(61)/2

    d = 3904/2

    d = 1952
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