Quick algebra help.?

Question

when I Have: 2*((3x-1)(3x-1)) I am confused. When I distribute 3x into 3x Do i get 3x^2? 6x^2? or 9x^2. Thanks again

Answer 1

It would be 9x^2 because you are squaring the whole 3x so (3x)^2 therefore you have to square both the 3 and the x. 3^2*x^2 which would simplify down to 9x^2

The rest of the problem...

2*((3x-1)(3x-1)) =

2*(9x^2 - 6x + 1) =

18x^2 -12x + 2 = FINAL ANSWER

Answer 2

3x * 3x = 3 * x * 3 * x = 3 * 3 * x * x = 9 x^2

Answer 3

when you distribute you will get:

[(9x^2) - (3x) - (3x) +1] * 2

(18x^2) - 6x - 6x + 2

(18x^2) -12x + 2

Answer 4

you get 9x^2

Answer 5

2 ( 3x - 1 ) ( 3x - 1 )

2 ( 9x ² - 6x + 1 )

18x ² - 12x + 2

Answer 6

2*((3x-1)(3x-1))=

2*(3x-1)^2=

2(9x^2+1-6x)=

18x^2+2-12x.

Answer 7

i don't quite get your question. This expression doesn't have 3x going into anything.

2*((3x-1)(3x-1)) is the same as:

2 * (9x² -6x + 1)

18x² -12x + 2

Answer 8

good luck!

Answer 9

2(9x^2+1-6x)

Answer 10

u would get 9x^2. just think of it like this: F.O.I.L. First Outer Inner Last.