Quick math question....?

Question

Simple

well not that simple because if it was i would have know it..

but thanx anyway guyz

ok

Y^2=25-X^2

and can u please tell me now you got to the answer

thanx

Answer 1

solve it for y?

y^2 = 25 - x^2

y = square root of (25 - x^2)

solve for x?  y^2 = 25 - x^2

       y^2 + x^2 = 25

x^2 = 25 - y^2

x = square root (25 - y^2)

simplify it  --->       y^2 = (5-x) (5+x)

Answer 2

There are two unknown values, so there can be more than one answer

Answer 3

what are you trying to solve... if you want to know the value of x and y, it is not possible for one cannot solve two variables with one equation, one needs a system of at least two...

but if you are solving for a circle...

(x-h)^2 + (y-k)^2 = r^2

the center is (0,0)... since h and k have no value...

radius is 5... the square root of 25...

  

Answer 4

y^2=25-x^2

y^2+x^2=25

sqrt x^2+y^2=25

       x+y= +5 or -5

Answer 5

General rules when solving equations...  you can only solve the equation for the unknowns  IF and only if you have as much unknown as the equation.

ie>  if you have 2 unknowns that you need to solve, you need 2 different equations (not multiples of the same equation)  and if you have 5 unknowns, you'd need five etc....

so in the above question, you have 2 unknown variables to solve, but only 1 equation, so it can't be solved with a definite distinct solution

good luck

Answer 6

it cant be solved because you need the value of x and y and normally you would just leave if but if you leave it as is, you canot do anthing because it is y to the second power equals 25 minus x to the second power. trust me i had this exact same problem on my homework and got it right.

Answer 7

If there no addition conditions:

(X,Y) are any points on the circle :

center at (0,0) radius=5

If give an additional condition:

such as:  X, Y both are positive  integers

=>  two solutions:  (3,4 ) or (4,3)

etc..