Reaction 3A+2B give 2C+D. [A]=0.01 [B]=3,rate appearance C=0.000008 order of reaction,rate law,rate constant?

Question

[A] and [B] in mole/L

Answer 1

if you are saying that  " 3A+2B -->  " is the rate determining step, then we can do this problem...

Rate Law:

Rate = k [A]^3 [B]^2

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order of reaction is...:

3 with respect to [A]

2 with respect to [B]

5 overall

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rate constant:

Rate = k [A]^3 [B]^2

0.000008 = k 0.01]^3 [3]^2

k = 0.88888

your answer is: k = 0.9