Read the details and please answer this math problem for me!?

Question

The length of the rectangle is 4 less than three times the width. If the perimeter is 88 cm., what are the dimmensions of the rectangle? can someone help me with this? answer this for me please!

Answer 1

L = 3W - 4

88 = 2(3W -4) + 2W

88 = 6W - 8 + 2W

88 = 8W - 8

96 = 8W

W =12 cm

L = 3(12) - 4 = 32 cm

Answer 2

88 = 2w + 2l

l = 3w-4

88 = 2w+2(3w-4)

88 = 2w+6w-8

96=8w

w=12

88=2(12)+2l

88=24+2l

64=2l

l=32

Answer 3

Let L = length and W = width

Since the length is 4 less than 3 times the width

L = 3W - 4

Perimeter = 2L + 2W = 88

So, we take our two equations and solve

L = 3W - 4 and 2L + 2W = 88

Plug the first equation into the second equation

2(3W - 4) + 2W = 88

Distribute

6W - 8 + 2W = 88

Collect like W terms

8W - 8 = 88

Add 8 to both sides

8W = 96

W = 12

Since L = 3W - 4

L = 3(12) - 4 = 36 - 4 = 32

Answer: Width = 12, Length = 32

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