Rearranging an equation into the form y = ax + c. Help?

Question

The equation is 2y = 5x + 6.

I'm familiar with the basic theory of inverse operations and all, but I just don't know how to go about answering this equation. Could somebody please take me thru it step-by-step? I really do want to learn.

10 points to best answer, and thank you so much!

x-posted to homework help.

Answer 1

If you're trying to get this into the form of y = mx + b, just divide both sides by 2.

y = (5x + 6) / 2

y = (5/2)x + 3

Answer 2

Your target format is  "  y = ax + c"  

so you want to get "y" alone (not 2y, 3y, or 5/2 y etc..) on one side of the equation...

you have    2y=5x + 6

inorder to get your equations to 1 "y", right now it is 2*y = .......

so you multiply by it's reciprical , or 1/2

so you're have  :    2y (1/2) = y

that's the left side of the equations,  since you multiplied the left by "1/2", you need to do the same to the other side...

thus:   1/2 *  (5x+6)  --->   1/2 * 5x +  1/2 * (6)  -->   5/2 x + 3

combine the two sides... you'll get

y = 5/2 x + 3       and   a = 5/2    c = 3

good luck