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for: Cl2(g) --> HCl0 Cl-i know the reduction is 2e- Cl2 --> 2Cl-but I can't figure out the oxidation. Cl2 --> HCl0? Where do the electrons go? What is the oxidation state of HClO? (I thought H (-1) Cl (-1) O( 2) but that doesn't seem to fit with the (0) oxidation state of Cl2. ) Any help would be appreciated!
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