Question:

2ax/4b + 3c/2d - x = 1?

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Please solve the equation for the variable x

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  1. (2ax/4b)-x=1-(3c/2d)

    x(a/2b-1)=(2d-3c)/2d

    x=(2d-3c)/2d * 2b/(a-2b)

    x= b(2d-3c)/d(a-2b)


  2. 2ax/4b + 3c/2d - x = 1

    2adx/4bd + 6bc/4bd - 4bdx/4bd = 1

    (2adx + 6bc - 4bdx)/4bd = 1

    (adx + 3bc - 2bdx)/2bd = 1

    adx + 3bc - 2bdx = 2bd

    x(ad - 2bd) = 2bd - 3bc

    x = (2bd - 3bc)/(ad - 2bd)

    x = (b[2d - 3c])/(d[a - 2b])

    Answer: x = (b[2d - 3c])/(d[a - 2b])

  3. 2ax/4b + 3c/2d - x = 1

    ax/2b - x = 1 - 3c/2d multiply both sides by 2bd

    adx - 2xbd = 2bd - 3bc

    x(ad - 2bd) = 2bd - 3bc

    x = (2bd - 3bc) / (ad - 2bd)

    x = b(2d - 3c) / d(a - 2b)

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