Algebra about Quadratic Equation?

Question

can you show me how to answer this and how could you get this?

My teacher said to find the root...

this is the problems:

2x^2 = 4 and 2(x-2) = 2

_____

3

Answer 1

i dunno know what is your question...

so... i will assume that your question are...

2x^2 / 3 = 4

and

2(x - 2) = 2

therefore...

2x^2 = 4(3)

2x^2 = 12

x^2 = 6

x = +/- sqrt 6

2(x -  2) = 2

x - 2 = 2/2

x = 1 + 2

x = 3

Answer 2

2x² = 4   /:2

x² = 2

x1;2 = +-(2)^0.5      there is ur root ( )^0.5

2(x-2) = 2   /:2

x-2 = 1       /+2

x = 3

Answer 3

Is thefirst (2x^2)/3? then it means x^2 = 6 or x = rt6.

Second means x - 2 = 1 so x = 3.

Second is not a quadraticc.