Algebra help please!?

Question

The two points are (-7,-2) and (1,6). How do you express the line going through the two points in standard form (Ax+By+C=0). I keep getting the wrong answer but I can't identify my mistake. Please help this is bugging the heck out of me!

Answer 1

find the slope. did you get 1?

put (1,6) into point-slope form

y-6=1(x-1). or just y-6=x-1

subtract y from each side

-6=x-y-1

add six to both sides

0=x-y+5

is this the right answer? you might have also gotten -x+y-5=0. that's also correct.

Answer 2

y2 - y1

---------- = slope

x2 - x1

y - y1 = m ( x - x1)

Done

Answer 3

First find the slope

((-2) - 6)/((-7) - 1)=(-8)/(-8)=1

slope=m=1

then find y intercept using the point (1,6) and ur slope

y=mx +b

6=(1)(1)+b

b=5

then substitute into equation

y=mx+b

y=1x+5

or in other words...

-1x+1y=5

-x+y=5

Answer 4

slope = (y2-y1) / (x2-x1)

            (6- -2) / (1 - -7)

              8 / 8 = 1

point slope form   y - y1 = m(x-x1)

                          y - 6 = 1 ( x-1)

                          y - 6 = x - 1

                          y = x + 5

     x - y + 5 = 0  when the equation is rewritten in standard form