Question:

Bus prob easy one?

by  |  earlier

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A bus started from the bus stand at 8 AM and after staying 30 minutes at a destination returns back to the bus stand. The Destination is 27 miles from the bus stand. The Speed of the bus is 18mph. In the return journey the bus travels with 50% fast speed.

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  1. My brain hurts just from trying to figure out what the question is here. But wait!!!! There isn't one, just really bad english!

    "the bus travels with 50% fast speed" .......huh?

    Sorry kiddo, I like problems like these, but your description doesn't make sense, and there is no question for anyone to try to answer.


  2. if u are tryin to ask, at wat time does the bus get back.

    the formula is tht TIME =DISTANCE/SPEED

    towards the destination:

    27/18 =1.5;

    1.5*60=90 which is 1 hour and 30 mins

    so  the bus reach the destination at 9.30 AM

    Stays there for 30 mins and strats at 10 AM again

    this time at a speed 50% more.

    so its 18+18*50%; which is 27

    and so again applyin the above formula

    27/27=1hour

    hence the bus reach the bus stand at 11AM
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