C=(2a-b)/(a+d) solve for a?

Question

Okay I got a=2d/b... however I did not solve it the way the teacher had asked, so can you explain to me the way you would solve it? (P.s. my answer works, but It isn't neccesarily the right one, so it doesn't have to be the same answer).

Answer 1

c(a+d) = 2a - b

ca + cd = 2a - b

ca + cd - 2a = -b

ca - 2a = -b - cd

a(c-2) = -b-cd

a =

-b-cd

-------

c-2

Answer 2

c = (2a - b)/(a + d)

c(a + d) = 2a - b

ca + cd = 2a - b

ca - 2a = - cd - b

a(c - 2) = - cd - b

a = - (cd + b)/(c - 2)

Answer: a = - (cd + b)/(c - 2)

Answer 3

OK

First, multiply both sides by a+d

c(a+d) = 2a-b ; now expand

ca + cd = 2a -b  ;now add b to both side

ca + cd + b = 2a ; now subtract ca from both sides

cd + b = 2a - ca ; now factor the right side

cd + b = a(2-c) ; now divide by 2-c

(cd + b)/(2-c) = a

Hope that helps.

Answer 4

set each set equal to zero

2a - b = 0

isolate the variable

2a = b

divide by 2

a = 1/2 b

then the other...

a + d = 0

isolate variable

a = -d

so a equals both -d and 1/2 b

Answer 5

C=(2a-b)/(a+d)

ac+cd=2a-b  Multiply both sides with (a+d)

ac+cd+b=2a  Add b to both sides

a=ac/2+cd/2+b/2  Divide both sides by 2