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Can you Solve this Dilution problem?

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How many milliliters of 0.387 M CuSO4 contain 1.00g of solute? Can you please show me how you solved it.

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  1. ok if it is 0.387 M that means it has 0.387 moles X 159.55 grams per mole in each liter  soo0.387 x 159.55 = 61.75 grams /liter  = 0.0618 grams per mL  soo to get 1 gram of CuSO4   1 grams /0.0618 grams /mL = 16.37 mL

    Proof    16.18 mL x 0.387 M = 6.26 mmoles X 159.55 mg/mmole = 0.999grams  rounding


  2. it contains 16.7millitres
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