Condensed Electron Configurations?

Question

For Cobalt, would it be [Ar]4s^2 then what?

For Barium, would it be: [Xe]6s^2

For Samarium, would it be: [Xe]6s^2 5d^6

For Indium, would it be: [Kr]5s^2, then what?

Answer 1

Cobalt: [Ar] 4s2 3d7

Barium is correct.

Samarium: [Xe] 6s2 4f6

Indium: [Kr] 5s2 4d10 5p1