Easy algerbra help please?

Question

-3(x+5)=3(x-1)

3(a+1)-5=3a-2

5(f+2)=2(3-f)

5(p+3)+9=3(p-2)

1.2(x-2)=2-x

i know i have to distribute like terms then do the opposite operation but then i forget what to do

Answer 1

-3(x+5)=3(x-1)

-3x-15=3x-3

6x-3=-15

6x=-12

x=-2

3(a+1)-5=3a-2

3a+3-5=3a-2

-2=-2

a=infinite number of solutions

5(f+2)=2(3-f)

5f+10=6-2f

7f+10=6

7f=-4

f=-4/7

5(p+3)+9=3(p-2)

5p+15+9=3p-6

2p+24=-6

2p=-30

p=-15

1.2(x-2)=2-x

1.2x-2.4=2-x

2.2x-2.4=2

2.2x=4.4

x=2

Answer 2

-3x-15=3x-3                  

-3x-3x=-3-15

-9x=-18

x= 2

Basically what you do is bring the x's to one side, and the numbers to the other and divide the number by the amount of x's

3a+3-5=3a-2

3a-2=3a-2              <--- With this problem, the answer cant be                                divisible by 0

3a-3a=-2+2

0a=0

Answer 3

for the first one you distribute the terms the equation becomes

-3x-15 = 3x-3

you add three to both sides to get one of the x's by itself

-3x-12 = 3x

you then add 3x to both sides to get both x's on one side

-12 = 6x

you dive by 6 to solve for x

x= -2

the rest can be solved the same way