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Help from a genius? Quick!!!!?

by  |  earlier

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Well Basically the question is very simple

How do you calculate the percentage by mass of fluorine in SnF2

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  1. mass of fluorine in SnF2=2x19

                                       =38

    molecular mass of SnF2=38+118.7

                                       =156.7

    percentage by mass of fluorine in SnF2 =[38/156.7]x100

                                                             =24.25016%

    [atomic mass of F=19  Sn=118.7]

            


  2. i dno im in year 9

  3. first, you have to find the atomic mass of  snF2.

    Then, you look in the periodic table to find the mass number of flourine.

    Finall to find the percentage of fluorine you just divide the atomic mass of snF2 by the mass number of flourine.

  4. [(mass of fluorine in SnF2)/(mass of SnF2)] × 100/1

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