Help solve this fraction question?

Question

Appreciate any help solving this problem

1/a = 1/b+c. Solve the fraction in terms of a (final answer should have a on one side and all other variables on the other side)

Answer 1

1/a = 1/b + c

1/a = (1 + cb)/b

Now take the reciprocal of both sides:

a = b/(a + cb)

If it's :

1/a = 1/(b + c)

Then just take the reciprocal:

a = b + c

Answer 2

You need to be clearer in your problem statement:

Is it 1/(b+c) or (1/b) + c?

If it is 1/a = (1/b)  +  c

Then it is

1 = (b/a) - bc

If it is 1/a = 1/(b+c)  then the solution is

1 = (b+c)/a

Answer 3

1/a = 1/b+c

a = b+c

Answer 4

the numerators are equal so the denominators are equal.

a = b + c

Answer 5

its simple

a= b+c

:)

Answer 6

assumming: 1/a = 1/(b+c) {cross multiply }

a *1 = 1*(b+c)

a= b+c {answer}

assumming:

             1/a = 1/b +c

              a(1/a) = a(1/b +c) {multiply both by 'a'}

                a/a   = a(1/b +c) {a/a =1}

                1     = a(1/b +c)   {divide both by (1/b +c)}

                1/(1/b +c) =a

                 b+ 1/c =a    {solution}

good catch minorchord!

Answer 7

1= a/(b+c)

a = b+c