Help with algebra 2? Easy 10!?

Question

So I'm a sophomore, taking a junior class in high school. I remember some algebra from when I took algebra 1. But today was my first day of algebra 2 and I'm having some trouble with some problems. Could someone please explain how to solve the following problems?

REDUCE.

1) 12y/8y^3

2) 2x^2/8x

3) 16x-24/4

EVALUATE. REDUCE ALL ANSWERS.

1) 2x/3y x 6/5

2) 9/4 divided by 1/5

3) 3/4 + 5/6

4) 2/5x - 3/2

EVALUATE. REDUCE ALL RADICALS.

1) Square root of 20.

2) Square root of 45.

SOLVE FOR X.

1) x+2/4 = 2x/5

EVALUATE THE FOLLOWING EXPRESSION IF X=-2/

1) 2/x + 4/x^2

If you could help with one, a few or all that would be just spiffy. Thanks!

Answer 1

Too many questions my friend !

Answer 2

I'll give you a sample of some of them.. Then you can refresh your memory.

Reduce #1

12y/8y^3

So, to reduce, you divide both top and bottom by anything common they share. Here, we have a 12 at the top and an 8 at the bottom. What's the common thing between 12 and 8? They can both be divided by 4. so it becomes,

12 divided by 4 is 3, 8 divided by 4 is 2

=> becomes 3y/2y^3

Three and two don't have anything in common right? So we can stop there for the numbers. Next, we go to the letters. y at top and y^3 at bottom. What's the common thing? They can both be divided by y. so just do that:

y divided by y is 1. y^3 divided by y is y^2. so it becomes:

3 times 1 / 2 times y^2

Final ANSWER => 3 / 2y^2

EVALUATE. REDUCE ALL ANSWERS. #1

This type of question is almost the same

2x/3y times 6/5

So you first deal with the times multiplication thing. Multiply the top with the top and the bottom with the bottom.

The things on top are:

2x and 6     => 2x times 6 is 12x

At bottom:

3y times 5 is 15 y

So it becomes, 12x / 15y

Take the common things between them. It's 3! So divide top and bottom by 3. 12x divided by 3 is 4x, and 15y divided by 3 is 5y

Final ANSWER: 4x / 5y

EVALUATE. REDUCE ALL RADICALS. #1

square root of 20.

For this type of question, you need to find out what each number is made up of. like in this case, 20 can be made up of:

1=> 20 times 1 = 20

2=> 10 times 2 = 20

3=> 5 times 4 = 20

Anything else? Nothing I guess... So, you find which set of these has numbers that can be square rooted. The only one is set 3 => 5 times 4. Because the square root of four is 2, right?

So it becomes like this:

=> Squareroot(20)

=> Squareroot(5 times 4)

=> Squareroot(5) times Squareroot(4)

=> Squareroot(5) times 2

=> 2 times Squareroot(5)

=> 2 Squareroot(5)

Hope you understand it... It's important...

Answer 3

For these, you reduce the numbers, then just subtract the variables.

Ex: 2)  2x^2/8x, reduce 2/8 to 1/4, then subtract x^2-x, which equals x

1) 3/2y^2

2) 1/4x

3) 4x-6

For these, you just need a common denominator. You find it by multiplying the two numbers under the line.

Ex: 2/5 + 1/2, so 5 x 2 = 10, making the fractions 4/10 and 5/10.

1) 12x/15y

2) 45/4

3) 38/24

4) don't know

For these, you need to know the perfect squares, like sqrt4 =2, sqrt16= 4, etc. It's kind of hard to explain them all.

1) 2sqrt5

2) 3sqrt5

You have to get rid of the five on the right side, so multiply both sides by 5.

Ex: x+2/4=2x/5

5x+10/4=2x

3x= -10/4

1) -5/6

Just subtitute -2 for x. So, it would be 2/-2 + 4/-2^2, then solve.

1) -1

Answer 4

Reduce

1.) 3/(2y^2)

2.) x/8

3.)2(8x-3)

Evaluate

1.) 4x/5y

2.)9/4/(1/5) = 9/4*(5/1) = 45/4

3.) 4.)for you

Evaluate

1.) sqrt 4*5 = 2*sqrt 5

2.) for you

Solve

1.) Multi both sides by common denominator 20 to get:

20x+10=8x

Add-8x and -10 to each side to get x's on one side and numbers on the other side

20x-8x=-10

12x=-10

x=10/-12 =-5/6

Evaluate the following

1.) if x=-2 substitute getting

(2/-2)+4/(-2)^2 = -1 + 1 = 0

Answer 5

1) 12y/8y^3 = 3/2y^2

lot of home work ??!

1) 2x/3y x 6/5 = 12x/15y = 4x/5y

I don't do Radicals any more ( Too old and tired), I just use my calculator. Sorry.

1) x + 2/4 = 2x/5 >> x - 2x/5 = - 1/2 >>>   5x-2x/5 = -1/2

3x/5 = -1/2>>> 6x = -5 >>> x = -5/6

1) 2/-2 + 4/4 >> -1 + 1 = 0

Regards.

Answer 6

I'll help you remember how to do it =)

1. First simplify the 12/8 (divide both by 4 to get 3/2). Then subtract the denominator exponent from the numerator. (so 1-3=-2) so you have 3/2x^2

2. Same thing, reduce the 2/8 (1/4). Then subtract exponents (2-1=1) so just x/4

3. I think you have a typo if not just reduce the last fraction.

1. 2*6=12 and 3*5=15 soooo 12x/15y. Reduce both by 3: 4x/5y

2. To divide fractions you "same change flip". Keep the first fraction the same, change the division sign to multiplication, and flip the last fraction: 9/4 * 5/1. Then just multiply numerators, then denominators, and simplify.

3. To add fractions, you have to find a common demominator (a number that both will go into evenly. 6 and 4 both go into 12) so it becomes 9/12+10/12=19/12

4. you can't simplify because they both don't have the x term

1. sqrt 20 = sqrt 4 * sqrt 5 = 2 sqrt 5

2. sqrt 45 = sqrt 9* sqrt 5 = 3 sqrt 5

1. x + 2/4 = 2x/5

  -x                 - x

   2/4 = 2x/5 - x

Find a common denomiator

2/4 = 2x/5 - 5x/5

2/4 = -3/5x      (I wrote it like this, which is the same thing to make it                    easier to get x by itself.)

2/4* -5/3 = x

-10/12 = x

-5/6 = x

1. The last one just plug in -2 for x.