How can i slove (logx)^2=9?

Question

How can i slove (logx)^2=9?

Answer 1

logx=the square root of 9 which is 3

x=10^3=1000

Answer 2

(logx)^2=9

SQRT (logx)^2= SQRT 9

logx = 3

10^3 = x

x = 1000

Think that's right, hope it helps.

Joe

Answer 3

I think all answers are correct but missing one solution.

if you take the squareroot of 9 then you should also account for -3 as a solution because -3 squared is 9.

the extra solution is:

log(x)=-3 => x=10^(-3), x=1/1000 check this answer and you will see that this is also a solution

Answer 4

find the square root of both sides

logx = 3

then raise ten to the power of each side

10^logx = 10^3

the 10^log cancels so you're left with

x=10^3

x=1000

that is assuming you aren't using natural logs

Answer 5

logx = sqrt 9

log x = 3

x = 10^3

x = 1000

Answer 6

log x = 3

x = 10³ (if logs are to base 10)

x = 1,000

Answer 7

(log x)^2 = 9

log x = +-3

x = 10^3 or x = 10^(-3)

x = 1000 or x = 0.001

Answer 8

(logx)^2 = 9

logx = sqareroot(9)

log x = 3

      x = 10^3     (the opposite of Log is 10^ )

       x = 1000

Answer 9

Take the square root of both sides of the equation:

    log x = 3

Then the inverse log of both sides:

    x = 1000

Answer 10

log x= +-3 so x=10^3 =1000 or x= 10^-3 =1/1000

Answer 11

Take the square root of both sides of the equation:

log x = 3 ,-3(log can not be negative)

so take logx=3

Then x=10^3=1000