How to calculate the molarity of

Question

steps pls?thnks (10 points!!)

Answer 1

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.because molarity is defined in terms of moles of solute and liters of solution, the given quantities are converted to moles and liters, respectively:

57.0 g CH3OH (1 mol CH3OH / 32.0 g CH3OH)   = 1.78 mol CH3OH

375 mL (1 L / 1000mL)  = 0.375 L

.alternatively, the number of moles can be changed to millimoles.

1.78 mol(1 mmol / 0.001 mol)  = 1780 mmol

M = 1780 mmol of CH3OH / 375 mL  = 4.75 M CH3OH

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Answer 2

molarity =mass of solute/molar mass of solute (1/volume of solution in dm3)

or

molarity = no. of moles of solute/volume of solution in dm3

if u ask some proper example,i can help u out by xplaining steps involved

Answer 3

There are many methods of approaching to molarity. The most straightforward way-

To calculate molarity, you need the mass of the substance, and the volume it is dissolved in. With the mass, you can calculate number of moles by using the formula- moles= mass/molecular mass.

Now you have the moles of the substance. This number of moles of the substance is included in the solution. You have the volume of the solution. The SI unit of molarity is mol dm^-3 or mol/L. Now, lets say the volume is V. Therefore the molarity is

moles * V/a

(where a is the conversion of unit, like if V is in cm^3 or mL, for example)

Answer 4

molar mass of CH3OH = 12+16+4=32

so 57g correspond to 57/32 =1.781mole this in 375mL = 0.375L

so in 1 liter molarity 1.781/0.375=4.75 mole/Liter

Answer 5

get the molecular weight of CH3OH

C=1x12=12

H=4x1=4

O=1x16=16

MW = 32

M=g solute/(MW x L solvent)

M = 57/(32 x 0.375) = 4.75

Answer 6

To calculate molarity you need to know the following:

molecular mass of the material

concentration of material in solution in g/L

Then divide the g/L by the molecular mass to get molarity of the solution.

Usually the problem breaks down into finding g/L from some other form of concentration (like g/cc, or µg/ml).  You have to convert those to g/L first.

To calculate the no of moles of a substance (not in solution), divide the mass in grams by the molecular mass.