I have an Algebra Question?

Question

Please explain how to do this problem:

Solve the equation for y. Then find the value of y for the given value of x.

3xy - 28 = 16x ; x = 4

Answer 1

3xy - 28 = 16x

3xy = 16x + 28

y = (16x + 28) / 3x

y = (16*4 + 28) / (3*4)

y = 90 / 12

y = 7.5

Answer 2

3xy - 28 = 16x

3xy = 28 + 16x

[factorise y, and let y = ]

y(3x) = 28 + 16x

y = (28 + 16x) / (3x)

Let x = 4,

y = [28 + 16(4)] / [3(4)]

y = 92 / 12

>>y = 23 / 3

Sorry if it's messed up =)

Answer 3

3xy = 16x + 28

y = 16/3 + 28/(3x)

-------------------->

y = 16/3 + 28/(3x) ; x = 4

y = 23/3