Question:

IM CONFUSED WITH ALGEBRAAAAAA?

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A car costs 16500.00 and 0.22 /km to operate. Another car costs 17200 and 0.20/km to operate. How many km must owners drive so that the costs of both cars are the same?

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  1. taking d to be the distance traveled

    16500.00 + 0.22d = 17200 + 0.2d

    rearrange to get

    0.02d = 700

    therfore

    d = 35000km


  2. Cost = initial cost plus cost per mile times number of kilometers

    so car 1 C=16500+.22(N)  where N=number of kilometers

    car 2      C=17200+.2N

    so setting costs equal

    16500+.22N = 17200 + .20N

    .02N =7000

    N = 350000 km

  3. Set it up so that 16500 + .22x = 17200 + .20x then solve for x

  4. 16500+.22m=17200+.2m

    .02m=700

    2m=70000

    m=35000

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