Length of the Hypotenuse.?

Question

In a right triangle suppose an acute angle measures 25 degrees. If the side opposite that angle is 12 inches long, what is the length of the hypotenuse to the nearest tenth of an inch?

So far I used the formula

csc= hypotenuse/ opposite ----->

25 degrees = x / 12 --->

x= 12 csc 25*

I am not sure if I am on the right track or totally lost. Please help!

10points! :]

Answer 1

That would be just what you want...

csc (25°) = 2.36620158

2.36620158 = hypotenuse/12

hypotenuse = 28.39441896

rounded to the nearest tenth of an inch = 28.4

Answer 2

You are totally on the right track.

Use your calculator to find csc 25° = 2.366

x = (csc 25°)(12) = 28.4"

Answer 3

there's definitely a mistake in the question because the answer which is 5.07 inches isn't good for a hypotenuse.

working:-

Sin.25 degrees = 12/hyp.

Sin.25 degrees*12 = 5.07in.