Physics homework! Help!?

Question

A motorcycle daredevil is attempting to jump across as many buses as possible (see the drawing). The takeoff ramp makes an angle θ = 17.2° above the horizontal, and the landing ramp is identical to the takeoff ramp. The buses are parked side by side, and each bus is 2.74 m wide. The cyclist leaves the ramp with a speed of v = 35.0 m/s. What is the maximum number of buses over which the cyclist can jump?

Answer 1

Vx

35* Cos( 17.2)=33.43 m/s

Vy

35* Sin( 17.2) =10.35 m/s

0=10.35-9.8.*t

t=1.07 seconds

total time =t*2=2.14 seconds up and down

s= 35* Cos( 17.2)*2.14=33.43*2.14=71.54 meters

buses =71.54/2.74

= 26.11

Answer 2

What's your problem with the equations of motion?

His vertical velocity v is 35 sin theta.

he rises and then sinks to landing ramp in  2t seconds,

where v = g *  t        (g is 9.8 m/s/s)

In 2t seconds he travels horizontal distance 35 cos theta

Finally divide that by 2.74 -> number of buses.

Now plug in the numbers.