(x+y)(x-y) for x=8 and y=3?

Question

n+60-n for n=12

4 n 6

Answer 1

Uhh??? Are these the same problem or what?

Anyways,

1) Substitute 8 for x and 3 for y;

(x+y)(x-y)=

(8+3)(8-3)=

(11)(5)=

55 :)

2) If n=12, then;

12+60-12=

72-12=60 ;)

3) "4 n 6"

this is where it gets tricky, because I'm not sure what exactly you mean.

If it's 4n6, then that's like 24n, and assuming n=12, then that's 24*12, which is 288.

If it's just a list, then go with "4 12 6"

p.S. Remember that people who take the time to study and listen in math class do better!

P.S.S. Srry, i hav an obsession w/smilies ;)

Answer 2

x=8 & y=3

Just plug the numbers to the corresponding variables.

(8 + 3)(8 - 3)

(11)(5) <== That's means multiply

55 <== That's your answer!

n+60-n n=12

12 + 60 - 12

72 - 12

60<== That's your answer!!

4n6

NOTE: when a varible and number are next to each other that means multiply.

4*12*6

48*6

288 <== That's your answer!!

Pay attention in your math class, it will help you understand more!! :]

Hope this helped!! :]

Answer 3

um..if im reading your question right all you have to do is put an 8 where theres and x and put a 3 where theres a y

(8+3)(8-3)= (11)(5)= 55

then where theres a n put a 12

12+60-12 thats just 60

and i dont know what that 4 n 6 is all about...

Answer 4

Have I missed something?  You have x and you have y.  Just plug in, add, subtract, and multiply.

The same for the second problem.  If you know n, just plug in and solve.