Removing a common factor inequalities?

Question

say you have -x^2-x+6>0 you have to common factor - rite but since you divide everything in left side by -1 you have to divide everything on right side by negative one as well? so -(x^2+x-6)<0 and -(x-2)(x+3) <0 rite

Answer 1

If a &gt; b then -a &lt; -b so if

-x^2 - x + 6 &gt; 0 then

x^2 + x - 6 &lt; 0

Note: If you multiply or divide each side of an inequality by a negative switch the order of the signs.

Yes... a/b = a * (1/b)  same difference