Rewrite the expression using positive exponents (-2)^0(3x^-2y^-2)^-1?

Question

Rewrite the expression using positive exponents (-2)^0(3x^-2y^-2)^-1?

Answer 1

(-2)^0(3x^-2y^-2)^-1

= 1(3^1 * x^-2 * y^-2)^-1

= 3^(1 * -1) * x^(-2 * -1) * y^(-2 * -1)

= 3^-1 * x^2 * y^2

= 1/3 * x^2 * y^2

= x^2y^2/3

Answer 2

Well -2^0 is just 1, as is any non-zero number raised to the power of 0.

And remember that a^-1 = 1/a.  So what you're left with is

1 / (3x^-2 y^-2)

But by the same "-1" principle, this is

(x^2 y^2) / 3

So that does it.  The exponents are now positive.  Though if you wanted to, you could simplify this further to

(xy)^2 /3