Running 5/6 of its original speed a train is 10 mins late,find its original time to cover the journey?

Question

Running 5/6 of its original speed a train is 10 mins late,find its original time to cover the journey?

Answer 1

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What we do here is "applied physics".  You've got 8800 tons but only 18 axles of dynamic brakes. (2 locomotives' dynamics are cut-out.)  Can you descend Donner Summit to Truckee safely?

Answer 2

Let v = original speed

Let d = distance of journey

Let t = time of journey

v = d/t

rearranging we get

t = d/v

d/v = time of original journey

d/(5/6*v) = time of late journey

d/(5/6*v) - d/v = 10 minutes ===> solve for d/v ratio

6/5*(d/v) - d/v = 10 minutes

1/5*(d/v) = 10 minutes

d/v = 50 minutes

50 minutes

Answer 3

50mph

Answer 4

Do your own homework