SERIOUSLY NEED ALGABRA HELP!!!!!?

Question

could use a little help here please

Thanks

Factoring first

24x - 3x(^2) - 36

and

a(^2) - 5a - 24

variables

x + x - 2

-- ---- = 3

3 5

and

n - 2n

--- --- = 5

2 9

I tried to make them as understandable as possible

if you could please explain how to do these be cause these are pretty much examples

Thanks so much

and yes its -36

I appreciate the answeres so far, but none of them are correct

for #1

my choises are

a) -3(x-6)(x-2)

b) (-3x-6)(x-2)

c) (-3x-4)(x-3)

#2

a) (a - 8)(a + 3)

b) (a + 8)(a - 3)

c) (a-3)(a-8)

#3

a) x=51/8

b) x=43

c) x=39/8

(their fractions)

#4

a) n = 18

b) n= (-)18

c) n= (-)9

but thank you 3 that answered

Answer 1

I'm not entirely sure what the question is for # 3 or # 4, but I can answer # 1 and # 2.

For factoring, all the equations are in the quadratic form ax^2 + bx + c. As long as a=1 (meaning the coefficient on the x^2 is 1), then you can factor using the way I'll tell you. Keep in mind though that if a doesn't equal 1 then there is another way to solve them, but since you don't have those I won't show it.

#!: Okay, the number one rule is that you factor out any like terms (numbers, variables) that ALL the terms share. They all share a -3 so factoring it out will give us...

     -3(-8x + x^2 + 12)

   Then, we need it in ax^2 + bx+ c format....

    -3(x^2 - 8x + 12)

   Next, we need to find two numbers that multiply to get 12 and add to get -8. That would be -6 and -2. So we put those in this format....

   -3(x-6)(x-2)     And you're done!!

#2: They don't share any like terms and a=1 so we can factor it. Again, we need to find two numbers that multipy to get -24 and add to get -5. That would be -8 and +3.

     (x-8)(x+3) And thats the answer!

Hope I helped! I'm a math tutor so I tend to ramble about these...

Answer 2

1#  24x-3x^2-36 = 0

-3(x^2 - 8x + 12) = 0

-3(x - 2) (x - 6)

The answer is a).



2# a^2 - 5a - 24 = 0

(a + 3) (a - 8)

The answer is a).

3# (x/3) + (x-2)/5 = 3

[(5x) + (3(x-2))]/15 = 3

(5x + 3x - 6)/15 = 3

8x - 6 = 3 times 15

8x = 45 + 6

x = 51/8

The answer is a).

4# (n/2) - (2n/9) = 5

((9n)-(4n))/18 = 5

5n = 5 times 18

n = 90/5

n = 18

The answer i s a).

Ok...all answer .... (a)......

Answer 3

1st problem:

1st factor:

24x - 3x² - 36 = 0

3x² - 24x = - 36

x² - 8x = - 12

x² - 4x = - 12 + (- 4²)

x² - 4x = - 12 + 16

(x - 4)² = 4

x - 4 = 2

x - 6 = 0

2nd factor:

x - 4 = - 2

x - 2 = 0

Answer: x = 6, 2; - 3(x - 6)(x - 2) are the factors

Proof (x = 6):

24(6) - 3(6²) = 36

144 - 3(36) = 36

144 - 108 = 36

36 = 36

Proof (x = 2):

24(2) - 3(2²) = 36

48 - 3(4) = 36

48 - 12 = 36

36 = 36

2nd problem:

1st factor:

a² - 5a - 24 = 0

a² - 5a = 24

a² - 5/2a = 24 + (- 5/2)²

a² - 5/2a = 96/4 + 25/4

(a - 5/2)² = 121/4

a - 5/2 = 11/2

a - 5/2 - 11/2 = 0

a - 8 = 0

2nd factor:

a - 5/2 = - 11/2

a - 5/2 + 11/2 = 0

a + 3 = 0

Answer: a = 8, - 3; (a - 8)(a + 3) are the factors.

Proof (x = 8):

8² - 5(8) = 24

64 - 40 = 24

24 = 24

Proof (x = - 3):

- 3² - 5(- 3) = 24

9 + 15 = 24

24 = 24

3rd problem:

x/3 + ([x - 2]/5) = 3

5x + 3(x - 2) = 45

5x + 3x - 6 = 45

8x = 51

x = 51/8

Answer: x = 51/8 or 6 3/8

Proof:

([51/8]/3) + ([51/8 - 2]/5) = 3

17/8 + ([51/8 - 16/8]/5) = 3

17/8 + ([35/8]/5) = 3

17/8 + 7/8 = 3

24/8 = 3

3 = 3

4th problem:

n/2 - 2n/9 = 5

9n - 4n = 90

5n = 90

n = 18

Answer: n = 18

Proof:

18/2 - (2[18])/9 = 5

9 - 36/9 = 5

9 - 4 = 5

5 = 5

Answer 4

1)

24x - 3x^2 - 36

= -3x^2 + 24x - 36

= -3(x^2 - 8x + 12)

= -3(x^2 - 2x - 6x + 12)

= -3(x - 2)(x - 6)

(answer a)

2)

a^2 - 5a - 24

= a^2 + 3a - 8a - 24

= (a^2 + 3a) - (8a + 24)

= a(a + 3) - 8(a + 3)

= (a + 3)(a - 8)

(answer a)

3)

x/3 + (x - 2)/5 = 3

15[x/3 + (x - 2)/5] = 15[3]

5x + 3(x - 2) = 45

5x + 3x - 6 = 45

8x = 45 + 6

8x = 51

x = 51/8

(answer a)

4)

n/2 - 2n/9 = 5

18(n/2 - 2n/9) = 18(5)

9n - 4n = 90

5n = 90

n = 90/5

n = 18

(answer a)

Answer 5

Do you have any idea what a pain in the backside it is having all that junk between the questions and the answer box?

1)

24x - 3x² - 36 =

-3(x² - 8x + 12) =

-3(x - 6)(x - 2)

2) a² - 5a - 24 = (a - 8)(a + 3)

3)

x/3 + (x-2)/5 = 3

lcd of 3 and 5 is 15, so multiply every term by 15

15(x/3) + 15(x-2)/5 = 15(3)

5x + 3(x-2) = 45

5x + 3x - 6 = 45

8x = 51

x = 51/8

4)

n/2 - 2n/9 = 5

multiply all terms by 18

18(n/2) - 18(2n/9) = 18(5)

9n - 4n = 90

5n = 90

n = 18

algEbra has an E

choiCe has 2 C's

Answer 6

24x - 3x(^2) - 36

= -3(x^2 -8x + 12) = -3(x-6)(x-2)

a(^2) - 5a - 24 = (a-8)(a+3)

x + x - 2

-- ---- = 3

3 5

I take this to mean x/3 + (x-2)/5 = 3 Multiply by 15 getting:

5x +3x-6 = 45

8x = 51

x = 51/8 = 6 3/8

n - 2n

--- --- = 5  I take this to mean n/2 -2n/9 = 5

2 9

Multiply by 18 getting:

9n - 4n = 90

5n = 90

n = 18