SIMPLE MATH QUESTION...HELP!?

Question

(2t)^-6

Please simplify with positive exponents.

Answer 1

Sorry the first answer is wrong.

2 is inside the parentheses so it should be

1/64t^6

Answer 2

Rule 1: raising a nonzero number to the −1 power produces its reciprocal. Thus, a^(-n) = (a^n)^-1 = 1/(a^n)

Rule 2: (ab)^n = a^n * b^n

So,

(2t)^-6 = ((2t)^6)^-1 = 1/(2t)^6 = 1/((2^6)*(t^6)) = 1/(64t^6)

Answer 3

1/ 2t^6