Science Question on Water and Hexane?

Question

If you had 250 grams of hexane at 4°C, how much thermal energy would it take to raise the temp to 23°C? Assume the thermal energy needed to raise the temperature was obtained by placing the container in water at 30°C. How much water would you need? (Remember that both liquids will end up at 23°C)

Answer 1

(250 g)(2.26 J/g°C)(23°C - 4°C) = m(4.184 J/g°C)(30°C - 23°C)

m = (10,735 g)/29.288 ≈ 366.5324 g ≈ 367 g or 367 ml