Show every possible 4 digit combination for numbers 0-9?

Question

Show every possible 4 digit combination for numbers 0-9?

Answer 1

Assuming

(1) that you are allowed to use a digit more than once and

(2) that you include numbers with one or more leading zero as a four digit combination

all of the other answers indicating there are 10,000 combinations are correct.

Assuming

(1) that you are NOT allowed to use a digit more than once and

(2) that you include numbers with one or more leading zero as a four digit combination

there are 10 x 9 x 8 x 7 = 5,040 combinations

Assuming

(1) that you are allowed to use a digit more than once and

(2) that you DO NOT include numbers with one or more leading zero as a four digit combination

there are 9 x 10 x 10 x 10 = 9,000 combinations, from 1,000 to 9,999.

Assuming

(1) that you are NOT allowed to use a digit more than once and

(2) that you DO NOT include numbers with one or more leading zero as a four digit combination

there are 9 x 9 x 8 x 7 = 4,536 combinations.

No matter which of these assumptions you make there are too many combinations to show them all in the space provided for a response.

Answer 2

go into microsoft excel or openoffice calc, in cell A1, format it to have display for numbers and type the number 1, click out of it.... it will display 0001, then click the little black box and pull down and it will automatically change the lower box's to, 0001,0002,0003 and so on... pull down until you reach 9999, thats all the number combinations of 4 numbers with 0-9

Answer 3

just start counting 0000 through 9999.  That's 10,000 combinations.

Answer 4

I think there is a formula for this - but I am no math whiz.

You said four digit combo - using digits 0-9.

I believe you use the possible number of digits, which is 10.

Then you multiply by the next number of possible digits, which is also 10, etc., etc., for the total of 4 digits in the combo.

So this should be your formula.

10 x 10 x 10 x 10 = 10,000

Answer is 10,000.

Good luck.

Answer 5

The number of possible combinations (10 in this case) to the power of the number of instances in the series (4).  So that's how we get to 10,000

If there were letters and numbers both then the answer would be 36 (10 numbers and 26 letters) to the 4th power or 1,679,616.

A.J.

http://kingcobrapoker.com