Simple equation of lithium hydroxide and sulfuric acid

Question

10.0 grams of solid lithium hydroxide is added to an aqueous solution of sulfuric acid. How many grams of lithium sulfate can be produced?

The equation i came up with is : Li2O (s) H2SO4 (aq) >> LiSO4 (aq) H2O (l)

Then I multiplied 10.0 by 109.95 (the atomic mass of LiSO4) and then divided the product by 29.88 (the atomic mass of Li2O) and my answer came out to be 36.80 grams. Is my answer correct? Also, i know this is a double replacement reaction. I also wanted to know if my phases of matter in the products are correct. thanks

Answer 1

Li2O is lithium oxide not lithium hydroxide (LiOH)

Answer 2

OK, Zuya, again your reasoning is correct, but your formula is wrong - it's Li2SO4. Interestingly, you calculated the molecular mass (not the atomic mass) correctly. So the answer is:

10 x 109.95/29.88 = 36.90