Simple physics Q. - vector and equilibrium ?

Question

An object of 0.5kg mass is pulled by a force F at an angle of 60° from the horizontal. If it encounters a friction of 5N, what is the value of F?

a)2N

b)5N

c)7N

8) 14 N

it has a diagram but i think the question supplied everything needed i suppose.. in the diagram its pulled to the left (if it matters) and the friction is to the right, naturally. and thats about it

thxx!!

Answer 1

The post above is correct.

If the mass is moving with constant velocity (in equilibrium),

The question should be: what is the value of F*cos(60)=5N

b)

Answer 2

it depends whether the object is being supplied enogh force to move. if it isnt the force would be less than or equal to 10N (5 / cos 60)newtons.

if it is moving which i assume it is it only leaves one option 14N. to get an absolute answer we need to know if it accelerating or moving constantly or stationary.

Answer 3

This question can't be answered without knowing if the object is in equilibrium(accelerating) or if it is even moving.