Simplify [(3/4)^2 - (1/3)^3] * 3^2.?

Question

help plz

Answer 1

for (3/4)^2.........

3^2   /   4^2    =    9/16

for (1/3)^3..........

1^3    /   3^3     =   1/27

for 3^2   =   9

combining 'em all...

STILL FOLLOWING THE  SIGNS...

(9/16  -  1/27) (9)

(227/432) (9)

(227/48)------------------------------...

or

4  35/48

  

Answer 2

[(3/4)^2 - (1/3)^3] * 3^2

Parentheses first...

[9/16 - 1/27](3/2)

= (227/432)(3/2) = 227/288

Take care,

David

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Answer 3

[(3/4)^2 - (1/3)^3] * 3^2

(3/4)^2 = 3/4 * 3/4 = 9/16

(1/3)^3  = 1/3 * 1/3 *1/3  =  1/27

3^2   = 3*3  = 9

(9/16  - 1/27) *9

(9*27  - 16)/(16*27) *9

(243 -16)/(16 * 3)

227/(16* 3)

227/48  = 4.73

Answer 4

[(3/4)^2 - (1/3)^3][3^2]

= [9][3^2/4^2 - 1^3/3^3]

= [9][9/16 - 1/27]

= 9*9/16 - 9*1/27

= 81/16 - 1/3

= (81/16)(3/3) - (1/3)(16/16)

= 243/48 - 16/48

= 227/48

Answer 5

looks hard

Answer 6

(9/16-1/27)*9=

[(27x9-16)/(27x16)]*9=

(243-16)/(3x16)=

227/48