Simplify the following expression?

Question

I've been stuck on this one problem, and any help would be greatly appreciated!

ln(sin(π/2) + cos³(-π/2) + e^cos0 - e^sin0 =

Answer 1

sinπ/2 = 1

cos-π/2 = 0

cos0 = 1

sin0 = 0

.. . .

ln 1 = 0

thus

0 + 0^3 + e - 1

= e - 1

.. . .. .