Simplifying Square Roots with Variables?

Question

i can't make thous square root sign things if you know what i mean so i'll put a / to represent it

1: / 72a^2b^3

2: /75xy^4

3: /18a

4: /x^9

5: /4x^5

6: /9s^6x

7: /16a^3b^4c

Answer 1

1.   6ab*sqrt(2b)

2.   5y^2*sqrt(3x)

3.    3(2a)

4.    l x^(9/2) l

5.   2x^(5/2)

6.    3 ls^3 lsqrt(x)

7.    4ab^2*sqrt(ac)

Answer 2

In Yahoo! Answers, You can actually just use sqrt() around the value that's supposed to be under the square root sign.

1: sqrt(72a^2b^3) =

sqrt(36 * 2 * a^2 * b^2 * b) =

sqrt(36) * sqrt(2) * sqrt(a^2) * sqrt(b^2) * sqrt(b) =

6 * sqrt(2) * a * b * sqrt(b) =

6ab * sqrt(2 * b) =

6ab sqrt(2b)

2: sqrt(75xy^4)

sqrt(25 * 3 * x * y^4) =

sqrt(25) * sqrt(3) * sqrt(x) * sqrt(y^4) =

5 * sqrt(3) * sqrt(x) * y^2 =

5y^2 sqrt(3 * x) =

5y^2 sqrt(3x)

3: sqrt(18a)

sqrt(9 * 2 * a) =

sqrt(9) * sqrt(2) * sqrt(a) =

3 * sqrt(2) * sqrt(a) =

3 * sqrt(2 * a) =

3 sqrt(2a)

4: sqrt(x^9) =

sqrt(x^8 * x) =

sqrt(x^8) * sqrt(x) =

x^4 * sqrt(x) =

x^4 sqrt(x)

5: sqrt(4x^5)

sqrt(4 * x^5) =

sqrt(4) * sqrt(x^5) =

2 * sqrt(x^4 * x) =

2 * sqrt(x^4) * sqrt(x) =

2 * x^2 * sqrt(x) =

2x^2 sqrt(x)

6: sqrt(9s^6x)

sqrt(9 * s^6 * x) =

sqrt(9) * sqrt(s^6) * sqrt(x) =

3 * s^3 * sqrt(x) =

3x^3 sqrt(x)

7: sqrt(16a^3b^4c)

sqrt(16 * a^3 * b^4 * c) =

sqrt(16) * sqrt(a^3) * sqrt(b^4) * sqrt(c) =

4 * sqrt(a^2 * a) * b^2 * sqrt(c) =

4b^2 * sqrt(a^2) * sqrt(a) * sqrt(c) =

4b^2 * a * sqrt(a) * sqrt(c) =

4ab^2 * sqrt(a * c) =

4ab^2 sqrt(ac)