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Simplifying the expression [AB+ABC+AB(CD+AD+AB.CD)] using Boolean algebra will give.?

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ABD, AB(CD.AD) ABCD AB

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  1. [AB+ABC+AB(CD+AD+AB.CD)

    = AB( 1+ C +CD+AD+AB.CD))

    = AB. 1 as 1 + anything = 1

    = AB

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