Simultaneous equations solved by substitution?

Question

a=4-2c

a=6c

Answer 1

6c = 4-2c

8c=4

c= 1/2

Answer 2

a = both of them so they both equal each other so

4-2c=6c  (plus 2c to both sides)

4=8c   (divide by 8)

1/2= c  (as the person above said)

Then found out a by putting your value for c back in to one of them

a= 6 * 1/2

a=3

Answer 3

a=6c

since a = 4-2c

4-2c=6c

8c=4

c=1/2

a=4-2*1/2

a=3

-Nandu

Answer 4

solution:

Q1→ a = 4-2c

Q2→ a = 6c

substitute:

4-2c = 6c

4 = 6c + 2c

4 = 8c

c = ½ → answer

then

a = 6c

a = 6(½)

a = 3 → answer

--regards--